1.

Which of the following contains the maximum number of atoms?

Answer»

10g of `CaCO_(3)`
4g of hydrogen
9g of `NH_(4)NO_(3)`
1.8g of `C_(6)H_(12)O_(6)`

Solution :1) `10gCaCO_(3)=(10)/(100)=0.1` moles
`=0.1N_(0)` MOLECULES
`=0.1N_(0)XX5` atoms
2) `4gH_(2)=(4)/(2)=2" moles "=2N_(0)xx2` atoms
3) `9gNH_(4)NO_(3)=(9)/(80)=0.1125` moles
`=0.1125N_(0)xx9` atoms
4) `1.8gC_(6)H_(12)O_(6)=(1.8)/(180)=0.01` moles
`=0.01N_(0)xx24`


Discussion

No Comment Found