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Which of the following curve is represented by 2x^(2)+6xy+5y^(2)=1? |
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Answer»
`2x^(2)+6xy+5y^(2)=1` By putting - x for x and - y for y, the equation REMAINS same, therefore the curve is symmetric in opposite QUADRANTS. Putting `x = 0, 5y^(2)=1` `impliesy=pm(1)/(sqrt(5))` Putting `y=0, 2x^(2)=1` `implies y=pm(1)/(sqrt(2))` Then the curve passes through the points `(pm(1)/(sqrt(2)),0)` and `(0,pm(1)/(sqrt(5)))`. Thus, curve (c ) is the required curve. |
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