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| 1. |
Which of the following determine shortest and longest wavelengths in hydrogen atom spectrum ? |
| Answer» <html><body><p>`(1)/(lamda)=R((1)/(1^(2))-(1)/(oo^(2))),(1)/(lamda)=R((1)/(5^(2))-(1)/(6^(2)))`<br/>`(1)/(lamda)=R((1)/(2^(2))-(1)/(oo^(2))),(1)/(lamda)=R((1)/(5^(2))-(1)/(oo^(2)))`<br/>`(1)/(lamda)=R((1)/(3^(2))-(1)/(4^(2))),(1)/(lamda)=R((1)/(4^(2))-(1)/(5^(2)))`<br/><a href="https://interviewquestions.tuteehub.com/tag/none-580659" style="font-weight:bold;" target="_blank" title="Click to know more about NONE">NONE</a> of these </p>Solution :`(1)/(lamda)=R((1)/(1^(2))-(1)/(oo^(2))),(1)/(lamda)=R((1)/(5^(2))-(1)/(6^(2)))` <br/> First equation of option (A) shows <a href="https://interviewquestions.tuteehub.com/tag/series-1201802" style="font-weight:bold;" target="_blank" title="Click to know more about SERIES">SERIES</a> limit of Lyman series, which is in ultraviolet region. So `lamda` is minimum, second equation of option (A) shows first line of Pfund series, which is in <a href="https://interviewquestions.tuteehub.com/tag/infra-515954" style="font-weight:bold;" target="_blank" title="Click to know more about INFRA">INFRA</a> <a href="https://interviewquestions.tuteehub.com/tag/red-613739" style="font-weight:bold;" target="_blank" title="Click to know more about RED">RED</a> region and shows maximum wavelength.</body></html> | |