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Which of the following do you expect to be coloured out of Cr^(+) or Cu^(+) and why? |
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Answer» Solution :The electronic CONFIGURATIONS of `Cr^(+)` and `Cu^(+)` are `Cr^(+) :4S^(0)3d^(5)` `Cu^(+) :4s^(0)3d^(10)` `Cr^(+)` has unpaired ELECTRONS in the d-subshell and is, therefore, coloured. On the other HAND, `Cu^(+)` is colourless because it does not have unpaired electrons. |
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