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Which of the following equation has sum of roots 3?(A) 2x2 – 3x + 6 = 0(B) -x2 + 3x – 3 = 0(C) -√2 x2 – (3/√2)x + 1 = 0(D) 3x2 – 3x + 3 = 0 |
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Answer» Answer is (B) -x2 + 3x – 3 = 0 Sum of roots of option (A) = -b/a = 3/2 Sum of roots of option (B) = -b/a = 3 |
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