1.

Which of the following figures does not represent 1 mole of dioxygen gas at STP ?

Answer»

16 G of GAS
22.7 L of gas
`6.022xx10^(23)` dioxygen molecules
11.2 L of gas

SOLUTION :It is SAID that, 1 mole of a gas = gram moleculasr mass = Avogadros no. of molecules = 22.4 L at STP.
Thus, 1 mole of `O_(2)` gas = 32 g of `O_(2)=6.02xx10^(23)` molecules = 22.4 L of `O_(2)` at STP


Discussion

No Comment Found