Saved Bookmarks
| 1. |
Which of the following function is not continuous at x=0? |
|
Answer» `F(x)(1+2x)^(1//x),x NE 0` and `underset(x to 0)(lim)f(x)=underset(x to 0)(lim)(1+2x)^(1//x)=e^(2)""[becauseunderset(xto0)(lim)(1+lamdax)^(1//x)=e^(lamda)]` `thereforef(0)=underset(xto0)(lim)f(x)=e^(2)` `impliesf(x)` is CONTINOUS at x=0. Option (b), here, f(0)=-1. and `underset(xto0)(lim)FF(x)=underset(xto0)(lim)(sinx-cosx)=sin0-cos0=-1` `thereforef(0)=underset(xto0)(lim)f(x)=-1` `impliesf(x)` is continuous at x=0 option (c). here `f(0)=-1` and `underset(x to 0)(lim)f(x)=underset(x to 0)(lim)(e^(1//x)-1)/(e^(1//x)+1)=underset(xto0)(lim)(1-e^(-1//x))/(e^(-1//x))=1` `therefore f(0) ne underset(x to 0)(lim)f(x)impliesf(x)` is not continuous option (d), here f(0)=1 and `underset(xto0)(lim)f(x)=underset(x to 0)(lim)(e^(5x)-e^(2x))/(sin3x)xx(3x)/(3x)` `=underset(xto0)(lim)(e^(5x)-e^(2x))/(3x)xxunderset(xto0)(lim)(3x)/(sin3x)` `(1+(5x)/(1!)+((5x)^(2))/(2!)+ . . .)-` `=underset(xto0)(lim)((1+(2x)/(1!)+((2x)^(2))/(2!)+ . .))/(3x)""(because underset(xto0)(lim)(3x)/(sin3x)=1)` `=underset(x to 0)(lim)(((3x)/(1!)+(21x^(2))/(2!)+ . . .))/(3x)=1` `thereforef(0)=underset(xto0)(lim)f(x)=1`. `impliesf(x)` is continuous at x=0. |
|