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Which of the following functions of time represent (a) simple harmonic motion and b. periodic but not simple harmonic? Give the period for each case. (1) sin omega t -cos omega t 2. sin^(2)omega t |
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Answer» Solution :1. `SIN omega t -cos omega t =SQRT(2)[1/(sqrt(2)) sin omega t-1/(sqrt(2))cos omegat]` `=sqrt(2)[sin omega t "cos"(pi)/4-cos omega t "sin"(pi)/4]` `=sqrt(2)sin(omega t-pi//4)` This FUNCTION represents a simple harmonic motion having a period `T=(2pi)/(omega)` and a phae angle `(-pi//4)` or `(7pi//4)` 2. `sin^(2)omegat=(1-cos2omegat)/2=1/2-1/2cos 2omegat` The function is periodic having a period `T=pi//3omega`. It also represents a haromonic motion with the point ofequilibrium OCCURRING at 1/2 instead of zero. |
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