1.

Which of the following has maximum number of molecules ? (C = 12, O = 16, N = 14, H = 1)

Answer»

1 mole of `H_2O` gas
32 g of CO
2.24 L of `N_2` at N.T.P.
22 g of `CO_2`

Solution :(a)`6xx10^(23)`
(B) `(6xx10^(23)xx32)/(28) = 6.86xx10^(23)`
( C) `(6xx10^(23))/(22.4) xx2.24 = 6xx10^(22)`
(d) `(6xx10^(23))/(44)xx22 = 3xx10^(23)`
CORRECT ANSWER is (b).


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