1.

Which of the following has the highest bond order ?

Answer»

`N_(2)`
`O_(2)`
`He_(2)`
`H_(2)`

Solution :Molecular orbital configuration of
`N_(2)RARR sigma 1S^(2)sigma^(**)1s^(2)sigma 2s^(2)sigma^(**)2s^(2)PI 2p_(x)^(2)pi 2p_(y)^(2)sigma 2p_(z)^(2)`.
BOND ORDER `=(1)/(2)(10-4)=3`
`O_(2)rArr sigma 1s^(2)sigma^(**)1s^(2)sigma2s^(2)sigma^(**)2s^(2)sigma 2p_(z)^(2)pi 2p_(x)^(2)pi2p_(y)^(2) pi^(**)2p_(x)^(1)pi^(**)2p_(y)^(1)`
Bond order `=(1)/(2)(10-6)=2`
`He_(2)rArr sigma 1s^(2)sigma^(**)1s^(2)`, Bond order `=(1)/(2)(2-2)=0`
`H_(2)rArr sigma 1s^(2)` , Bond order `=(1)/(2)(2-0)=1`


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