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Which of the following has the shortest bond length? NO, NO+, NO2+, NO-.

Answer» NONumber of electrons\xa0= 15Electronic configuration =\xa0{tex} \\sigma \\mathrm{1s}^{2}, \\sigma^{*} \\operatorname{1s}^{2}, \\sigma 2 s^{2}, \\sigma^{*} 2 s^{2}, \\sigma 2 p_{z}^{2}, {/tex}{tex} \\pi 2 p_{x}^{2}=\\pi 2 p_{y}^{2}, \\pi^{*} 2 p_{x}^{1} {/tex}Bond order\xa0=\xa0{tex}\\frac {1} {2}{/tex}(10 - 5) = 2.5Magnetic property = Paramagnetic.NO+Number of electron = 14Electronic configuration =\xa0{tex} \\sigma \\mathrm{1s}^{2}, \\sigma^{*} \\mathrm{1s}^{2}, \\sigma 2 s^{2}, \\sigma^{*} 2 s^{2}, {/tex}{tex} \\sigma 2 p_{z}^{2}, \\pi 2 \\rho_{x}^{2}=\\pi 2 p_{y}^{2} {/tex}Bond order =\xa0{tex}\\frac {1} {2}{/tex}(10 - 4) = 3Magnetic property = Diamagnetic.{tex} \\mathrm{N} O^{2+} {/tex}Number of electrons = 13Electronic configuration =\xa0{tex} \\sigma \\mathrm{1s}^{2}, \\sigma^{*} \\mathrm{1s}^{2}, \\sigma 2 s^{2}, \\sigma^{*} 2 s^{2}, {/tex}{tex} \\sigma 2 p_{z}^{2}, \\pi 2 \\rho_{x}^{2}=\\pi 2 p_{y}^{1} {/tex}Bond order =\xa0{tex}\\frac {1} {2}{/tex}\xa0(9 - 4) = 2.5Magnetic property = ParamagneticNO-Number of electrons = 16Electronic configuration =\xa0{tex} \\sigma \\mathrm{1s}^{2}, \\sigma^{*} \\mathrm{1s}^{2}, \\sigma 2 s^{2}, \\sigma^{*} 2 s^{2}, {/tex}{tex} \\pi 2 p_{x}^{2}=\\pi 2 p_{y}^{2}, \\pi^{*} 2 p_{x}^{2} {/tex}Bond order =\xa0{tex}\\frac {1} {2}{/tex}(10 - 6) = 2Magnetic property = DiamagneticSince\xa0{tex} \\mathrm{NO}^{+} {/tex}\xa0has the highest bond order and therefore, it has\xa0the shortest bond length.


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