1.

Which of the following have identical bond order ?

Answer»

`CN^(-)`
`NO^(+)`
`O_(2)^(-)`
`O_(2)^(2-)`

Solution :(A,B)
`CN^(-)`(NUMBER of electrons= 6 + 7 + 1 = 14)
`NO^(+)`(number of electrons= 7 + 8 - 1 = 14 )
`O_(2)^(-) `(number of electrons= 8 + 8 + 1 = 17)
`O_(2)^(2-)` (number of electrons = 8 + 8 + 2 = 18 )
so, `CN^(-) and NO^(+)` because of the presence of same number of electrons, have same bond order.


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