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Which of the following have identical bond order ? |
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Answer» `CN^(-)` `CN^(-)`(NUMBER of electrons= 6 + 7 + 1 = 14) `NO^(+)`(number of electrons= 7 + 8 - 1 = 14 ) `O_(2)^(-) `(number of electrons= 8 + 8 + 1 = 17) `O_(2)^(2-)` (number of electrons = 8 + 8 + 2 = 18 ) so, `CN^(-) and NO^(+)` because of the presence of same number of electrons, have same bond order. |
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