1.

Which of the following is/are correct about[Cu(NH_(3))_(4)]SO_(4) :

Answer»

It is a Tetrahedral complex
It is paramagentic with one UNPAIRED ELECTRON in the d-subshell
It gives WHITE precipitate with `BaCl_(2)`
Its aqueous solution does not conduct electricity.

Solution :In `[CU(NH_(3))_(4)]SO_(4)` complex one unpaired electron present in `P_(Z)`orbital
Hybridisation `= dsp^(2)` , square planner
`BaCl_(2) +SO_(4)^(2-) to BaSO_(4)` complex


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