1.

Which of the following is/are correct concentration term (s) for 11.2 volume H_(2)O_(2) solution ? (density of solution = 1.034 gm//ml )

Answer»

Molarity = 1
`% w//v = 3.4 %`
Molality = 1
`% w//w = 34%`

Solution :(A)`11.2 = 11.2 M` (M = molarity)
M = 1
1 MOLE in 1 litre solution
1 mole in 1034 GM solution(DENSITY of solution `= 1.034` gm/ml )
Mass of solvent `= 1034 - 34 = 1000 gm`
Molality (m) `= ("1 mole")/(1 kg) = 1m`
(C ) `% w//v = ("weight of solute")/("Volume of solution") xx 100 = (34)/(1000) xx 100 = 3.4%`
(D) `11.2 = 11.2 m`
`m = 1 rArr 1 "mole" H_(2)O_(2)` in 1000 mL solution
`rArr 34 gm H_(2)O` in 103 gm solution
`% w//w = (34)/(1034) xx 100 = 32.8 %`


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