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Which of the following is correct formula for braking torque in plugging?(a) n (ka^2/Rb)(b) n^2 (ka^2/Rb)(c) n^-1 (ka^2/Rb)(d) (ka^2/Rb)This question was posed to me in a job interview.My question is taken from Braking of DC Motors in section DC Motors of DC Machines

Answer»

Correct CHOICE is (a) n (ka^2/Rb)

Explanation: Braking TORQUE is equal to braking POWER divided by SPEED of the motor.

 T= [(nka )^2/Rb]/n. As, Braking power is equal to Ea^2/Rb/n. By solving for the braking torque from the above equation, we GET n (ka^2/Rb).



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