1.

Which of the following is correct option for free expansion of an ideal gas under adiabatic condition?

Answer»

`q=0,DELTAT LT0,w cancel(=) 0`
`q=0, DeltaTcancel(=) 0,w=0`
`qcancel(=) 0,DeltaT , w=0`
`q=0,DeltaT=0,w=0`

Solution :For adiabatic expansion, `q=0`
For free expansion, `P_(EXT) = 0`. Hence,`w-0`
`DeltaU = q+w=0+0=0`. As U is a function of TEMPERATURE `( U = (3)/(2) nRT)` and as `DeltaU = 0,:.DeltaT =0`


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