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Which of the following is formed, when copper (II) sulphate is treated with excess ammonia?A. A black precipitateB. A red precipitateC. A deep blue solutionD. A white precipitate turning black |
Answer» Correct Answer - C Tetraamino cupric ion is formed. `Cu^(+)+4NH_(3)rarr underset("Deep blue")([Cu(NH_(3))_(4)]^(2+))` |
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