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Answer» `UF_(4)` `PbCl_(2)` `SnCl_(2)` `UF_(6)` Solution :`UF_6` has ESSENTIALLY covalent character. This is because small HIGHLY charged cations POLARISE the anions more efectively. For a metal with variable oxidation states, the halide with higher oxidation state of metal will be more covalent than the halide with lower oxidation of the metal. For example, `PbCl_6, SnCl_4 and UF_6`, are more covalent in nature than `PBCI_2, SnCl_2 and UF_4` respectively.
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