1.

Which of the following is the radiation resistance of the Hertzian dipole?(a) \(\frac{\eta_0 w^2 dl^2}{6\pi c^2}\)(b) \(\frac{\eta_0 wdl^2}{6\pi c^2}\)(c) \(\frac{\eta_0 w^2 dl^2}{3\pi c^2}\)(d) \(\frac{\eta_0 w^3 dl^2}{3\pi c^3}\)I have been asked this question in an internship interview.Asked question is from Radiation topic in section Radiation, Baluns & Polarization of Antennas

Answer»

The correct choice is (a) \(\frac{\eta_0 w^2 dl^2}{6\pi c^2}\)

To explain: Radiation resistance of a HERTZIAN dipole is \(R_{RAD} = 80\pi^2(\frac{l}{\LAMBDA})^2\)

By simplifying the options GIVEN above,

\(\frac{\eta_0 w^2 dl^2}{6\pi c^2} = \frac{120\pi(2\pi/\lambda)^2 dl^2}{6\pi} = 80\pi^2(\frac{l}{\lambda})^2\)


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