`KMnO_(4)` `K_(2)Cr_(2)O_(7)` `KO_(2)` None of these.
Solution :`KMnO_(4)` is DARK pink COLOURED solid due to pink `MnO_(4)^(-)` ion, `K_(2)Cr_(2)O_(7)` is ORANGE coloured solid due to `Cr_(2)O_(7)^(2-)` ion and `KO_(2)` is an orange yellow coloured solid.