1.

Which of the following numbers is a perfect cubea) 141b) 294c) 216d) 496

Answer»

Firstly we have to find the factors for the above numbers

∛141 = \(\sqrt[3]{(3 × 47)}\)

∛294 = \(\sqrt[3]{(2 × 3 × 7 × 7)}\)

∛216 = \(\sqrt[3]{(6 × 6 × 6)}\)

∛496 = \(\sqrt[3]{(2 × 2 × 2 × 2 × 31)}\) 

From the above results, 216 has the perfect cube factors.

∴ 216 is the perfect cube.



Discussion

No Comment Found