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Which of the following numbers is a perfect cubea) 141b) 294c) 216d) 496 |
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Answer» Firstly we have to find the factors for the above numbers ∛141 = \(\sqrt[3]{(3 × 47)}\) ∛294 = \(\sqrt[3]{(2 × 3 × 7 × 7)}\) ∛216 = \(\sqrt[3]{(6 × 6 × 6)}\) ∛496 = \(\sqrt[3]{(2 × 2 × 2 × 2 × 31)}\) From the above results, 216 has the perfect cube factors. ∴ 216 is the perfect cube. |
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