1.

Which of the following orbitals are possible?

Answer»

1P
2S
2d
3f

Solution :1p is not possible because if `n=1` then `l=0` only and for p, `l=1`
2s is possible because if `n=2` then `1=0`, 1 and for s, `1=0`
2p is possible because if `n=2` then `1=0`, 1 and for p, `1=l`
3f is not possible because if `n=3` then `1=0`, 1 and 2 for f, `1=3`.


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