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Which of the following order of energies of molecular orbitals of N2 is correct?(i) (π2py ) < (σ2pz) < (π*2px) ≈ (π*2py)(ii) (π2py ) > (σ2pz) > (π*2px) ≈ (π*2py )(iii) (π2py ) < (σ2pz) > (π*2px) ≈ (π*2py )(iv) (π2py ) > (σ2pz) < (π*2px) ≈ (π*2py ) |
Answer» (i) (π2py ) < (σ2pz) < (π*2px) ≈ (π*2py) |
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