1.

Which of the following orders is/are incorrect ?

Answer»

`H_3PO_4 gt H_3PO_3 gt H_3PO_2`(reducing character)
`N_2O LT NO lt N_2O_3 lt N_2O_5` (oxidation state on nitrogen atom)
`NH_3 gt PH_3 gtAsH_3 gt SbH_3`(basicity)
`SbH_3 gt NH_3 gt AsH_3 gt PH_3` (reducing character )

Solution :(A)As number of reducing hydrogen increases , the reducing character ALSO increases . In `H_3PO_4` there is no reducing hydrogen so it should be least reducing . Correct ORDER is `H_3PO_2 gt H_3PO_3 gt H_3PO_4`
(B)+1 lt +2 lt +3 lt +5
(C )down the group the availability of lone pair of electrons DECRESES as they are present in more concentrated s-orbital
(D)As down the group bond energy decreases, the removal of H becomes easier. so correct order is `SbH_3 gt AsH_3 gt PH_3 gt NH_3`


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