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Which of the following orders is/are incorrect ?A. `H_3PO_4 gt H_3PO_3 gt H_3PO_2`(reducing character)B. `N_2O lt NO lt N_2O_3 lt N_2O_5` (oxidation state on nitrogen atom)C. `NH_3 gt PH_3 gtAsH_3 gt SbH_3`(basicity)D. `SbH_3 gt NH_3 gt AsH_3 gt PH_3` (reducing character ) |
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Answer» Correct Answer - A,D (A)As number of reducing hydrogen increases , the reducing character also increases . In `H_3PO_4` there is no reducing hydrogen so it should be least reducing . Correct order is `H_3PO_2 gt H_3PO_3 gt H_3PO_4` (B)+1 lt +2 lt +3 lt +5 (C )down the group the availability of lone pair of electrons decreses as they are present in more concentrated s-orbital (D)As down the group bond energy decreases, the removal of H becomes easier. so correct order is `SbH_3 gt AsH_3 gt PH_3 gt NH_3` |
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