Which of the following outer electronic configuration may exhibit the

1.	Which of the following outer electronic configuration may exhibit the largest number of oxidation states?(a) 3d3, 4s2(b) 3d5, 4s1(c) 3d5, 4s2(d) 3d2, 4s2
Answer» Answer is : (c) 3d⁵, 4s² The sum of number of electrons (unpaired) in d-orbital and number of electrons in s-orbital gives the number of oxidation states (OS) exhibited by d-block elements. Therefore, (a) 3d³, 4s²⇒ OS = 3 + 2 = 5 (b) 3d⁵, 4s¹⇒ OS = 5 + 1 = 6 (c) 3d⁵, 4s²⇒ OS = 5 + 2 = 7 (d) 3d², 4s²⇒ OS = 2 + 2 = 4 Hence, elements with 3d⁵, 4s² configuration exhibits largest number of oxidation states.

Which of the following outer electronic configuration may exhibit the largest number of oxidation states?(a) 3d3, 4s2(b) 3d5, 4s1(c) 3d5, 4s2(d) 3d2, 4s2

Answer»

Answer is : (c) 3d⁵, 4s²

The sum of number of electrons (unpaired) in d-orbital and number of electrons in s-orbital gives the number of oxidation states (OS) exhibited by d-block elements. Therefore,

(a) 3d³, 4s²⇒ OS = 3 + 2 = 5

(b) 3d⁵, 4s¹⇒ OS = 5 + 1 = 6

(d) 3d², 4s²⇒ OS = 2 + 2 = 4

Hence, elements with 3d⁵, 4s² configuration exhibits largest number of oxidation states.

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Which of the following outer electronic configuration may exhibit the largest number of oxidation states?(a) 3d3, 4s2(b) 3d5, 4s1(c) 3d5, 4s2(d) 3d2, 4s2

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