1.

Which of the following pairs of species have the same bond order-

Answer»

`O_(2),NO^(+)`
`CN^(-),CO`
`N_(2),O_(2)^(+)`
`CO,NO`

Solution :TOTAL no. of electrons PRESENT in `CN^(-)=14`
Total no. of electrons present in `CO=14`
MO electronic configuration of `CO-`
`(sigma_(1s))^(2)(sigma_(1s)^(**))^(2)(sigma_(2s))^(2)(sigma_(2p_(z)))^(2)(sigma_(2s)^(**))^(2)(pi_(2p_(X)))^(2)(pi_(2p_(y)))^(2)`
MO electronic configuration of `CN^(-)`-
`(sigma_(1s))^(2)(sigma_(1s)^(**))^(2)(sigma_(2s))^(2)(sigma_(2s)^(**))^(2)(pi_(2p_(x)))^(2)(pi_(2p_(y)))^(2)(sigma_(2p_(z)))^(2)` ltbgt bond order of `CO=(1)/(2)(8-2)=3`
Bond order of `CN^(-)=(1)/(2)(8-2)=3`


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