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Which of the following pairs will have the same number of atoms ? [ atme wt. H=1, O=16, C=12, Cl=35.5 g "mol"^(-1)] |
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Answer» 28 g CO and 36.5 g HCl `= 28 g "MOL"^(-1)` `:.28 g CO = 1 ` moleCO (ii) Molecular mass of HCL `=(1+35.5)` `= 36.5 f "mol"^(-1)` `:.36.5 g HCl = 1 ` mole HCl As CO and HCl both are 1 mole and they have same 2 atoms, hence will have same number of atoms (B) `44 g CO_(2) =1 "mole" CO_(2)` but `44g CO != 1 ` mole CO `:.` They do not have equal number of molecules (C) `14 g N_(2)` `= (14)/(28) "mole" N_(2)` `= 1/2 "mole" N_(2)` `28 g CO_(2)` `= (28)/(44) ` mole `CO_(2)` `= 0.63.63` mole `CO_(2)` `:. 14 g N_(2)` and `28 g CO_(2)` have have different moles and as a result different no. of molecules (D) `28 g N_(2)` `= (28)/(28) ` mole `N_(2)` ` = 1` mole `N_(2)` `=2` mole N atoms `18 g H_(2)O` `= (18)/(18) ` mole `H_(2)O` `= 1` mole `H_(2)O` ` = 3` mole atoms `:.N_(2)` and `H_(2)O` have different no. of atoms |
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