InterviewSolution
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InterviewSolution
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Which of the following product of `e , h , mu , G` ( where ` mu` is permeability ) be taken so that the dimensions of the product are same as that of the speed of light ?A. `he^(-2) mu^(-1) G^(0)`B. `h^(2) e G^(0) mu`C. `h^(0)e^(2) G^(-1) mu`D. `he^(-2) mu^(0)` |
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Answer» Correct Answer - A Here `v = e^(a) h^(b) mu^( c ) G^(d) `. Taking the dimensions, `M^(0) LT^(-1) A^(0)` ` = [AT^(1)] ^(a) [ML^(2) T^(-1) ]^(b) [ MLT^(-2) A^(-2)]^( c ) [ M^(-1) L^(3) T^(-2) ]^(d)` There will be four simultaneous equations by equating the dimensions of `M,L , T, and , A`. These are ` a-2c = 0 , a - b - 2c -2d = -1 , b+ c - d = 0 and 2b + c + 3d = 1`. Solving for `a , b , c and d`, we get ` a = -2 , b = 1 , c = -1 , d = 0` Thus , `v = e^(-2) h mu^(-1) G^(0)` |
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