InterviewSolution
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InterviewSolution
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Which of the following reactions is//are correct? |
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Answer» a.  So both the products are correct. `(snCl_(2)+HCl)` selectively reduces `(-NO_(2))` GROUP ortho to `(Me-) (EDG)` group, but `(NH_(4)SH)` selectively reduces `(-NO_(2))` group para to `(Me-) (EDG)` group. So both the products are correct. c. DUE to `(+I)` effect of three `(Me-)` groups, the benzene the ring is activated and is unstable. So the oxidation of benzene ring TAKES place, while due to the absence of benzylic H atom in t-butyl group, the oxidation of side chain does not take place. So the products `(II)` and `(III)` are correct, but product `(I)` is wrong. So the answer `(c )` is wrong. d.In acidic medium `(Sn+HCl)`, the `(-NO_(2))` group is reduced to `(-NH_(2))` group. So product `(I)` is correct. In neutral medium `(Zn+NH_(4)CL` or `Al-Hg(H_(2)O), (NO_(2))` group is reduced to `(NHOH)` group. So product `(II)` is correct. In basic with `Na_(3)AsO_(3)+overset(ɵ)(O)H, (-NO_(2))` group is converted to azoxy group, so product `(III)` is correct. Hemce, the answer are `(a), (b)`, and `(d)`. |
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