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Which of the following reactions will get affected by increasing the pressure ? Also mention whether change will cause the reaction to go into forward or backward direction ? (i)COCL_(2) (g) hArr CO(g) + Cl_(2) (g)(ii) CH_(4) (g) + 2 S_(2) (g) hArr CS_(2) (g) + 2 H_(2) S (g) (iii) CO_(2) (g) + C (s) hArr 2 CO (g)(iv) 2 H_(2) (g) + CO (g) hArr CH_(3) OH (v)CaCO_(3) (s) hArr CaO (s) + CO_(2) (g)(vi)4 NH_(3) (g) + 5 O_(2) (g) hArr 4 NO (g) + 6 H_(2) O (g) |
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Answer» Solution :Reactionsaffected will be those in which `(n_(p) != n_(r))_(gaseous)`. Hence , reactions (i), (III), (iv), (V) and (vi) will be affected . By applying Le Chetelier's principle , we can PREDICT the direction . Increase of pressurewill SHIFT the equilibrium to the side in whichthe number of moles is less. (i) `n_(p)=2, n_(r) = 1 , i.e, n_(p) gt n_(r) ,` reaction will go in the backward direction (ii)`n_(p)=3, n_(r) = 3 , i.e, n_(p) gt n_(r) ,`reaction will not be affected by pressure . (iii)`n_(p)=2, n_(r) = 1 , i.e, n_(p) gt n_(r) ,` reaction will go in the backward direction . (iv)`n_(p)=1, n_(r) = 3 , i.e, n_(p) gt n_(r) ,` reaction will go in the fiorward direction . (v) `n_(p)=1, n_(r) = 0 , i.e, n_(p) gt n_(r) ,` reaction WIL go in the backward direction. (vi) `n_(p)=10, n_(r) = 9 , i.e, n_(p) gt n_(r) ,`reaction will goo in the backward direction |
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