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Which of the following set of quantum numbers is correct for the 19^"th" electron of chromium

Answer»

`{:(N,L,m,s),(3,0,0,1//2):}`
`{:(n,l,m,s),(3,2,-2,1//2):}`
`{:(n,l,m,s),(4,0,0,1//2):}`
`{:(n,l,m,s),(4,1,-1,1//2):}`

Solution :`19^"th"` electron of chromium is `4s^1` n=4, l=0, m=0 , `s=+1/2`


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