1.

Which of the following shows nitrogen with its increasing order of oxidation number ?

Answer»

`NO LT N_(2)O lt NO_(2) lt NO_(3)^(-) lt NH_(4)^(+)`
`NH_(4)^(+) lt N_(2)O lt NO_(2) lt NO_(3)^(-) lt NO`
`NH_(4)^(+) lt N_(2)O lt NO lt NO_(2) lt NO_(3)^(-)`
`NH_(4)^(+) lt NO lt N_(2)O lt NO_(2) lt NO_(3)^(-)`

Solution :`{:("Compound","O.S. of N"),(N_(2)O," "+1),(NO," "+2),(NO_(2)," "+4),(NO_(3)^(-)," "+5),(NH_(4)^(+)," "-3):}`
Therefore increasing ORDER of oxidation state of N is :
`NH_(4)^(+) lt N_(2)O lt NO lt NO_(2) lt NO_(3)^(-)`


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