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Which of the following solutions will have pH close to 1.0 |
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Answer» 100 ml of (M/10) HCl + 100 ml of (M/10) NaOH So acid is left at the end of reaction `N_("FINAL solution") = [H^(+)] = (N_(1)V_(1) - N_(2)V_(2))/(V_(1)+V_(2))` `= ((1)/(5)XX 75-(1)/(5)xx 25)/(75+25) ` `= (1)/(10) = 0.1 = PH = -LOG[H^(+)] = 1` |
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