tion:5. The measures of two adjacent angles of a parallelogram are in the RATIO 3:2. Find the measure of each of the angles of the parallelogram.\begin{gathered}\begin{gathered}\begin{gathered}\\\\\sf \large \red{\underline{GIVEN:-}}\\\\\end{gathered}\end{gathered} < /p > < p > \end{gathered} Given:−

The measures of two adjacent angles of a parallelogram are in the ratio 3:2.\begin{gathered}\begin{gathered}\begin{gathered}\\\\\sf \large \red{\underline{To \: Find:-}}\\\\\end{gathered}\end{gathered} < /p > < p > \end{gathered} ToFind:−

Find the measure of each of the angles of the parallelogram.\begin{gathered}\begin{gathered}\begin{gathered}\\\\\sf \large \red{\underline{Solution :- }}\\\\\end{gathered}\end{gathered} < /p > < p > \end{gathered} Solution:−

\text{ \sf suppose the angles be equal to 3x and 2x} suppose the angles be equal to 3x and 2x\boxed{ \sf \orange{ we \: have \: ardjacent \: angles \: of \: a \: parallelogram \: = 180}} wehaveardjacentanglesofaparallelogram=180 \begin{gathered}\begin{gathered}\begin{gathered}\\ \sf \underline{ \GREEN{putting \: all \: values : }}\end{gathered}\end{gathered} \end{gathered} puttingallvalues: \begin{gathered}\begin{gathered}\begin{gathered}\: \\ \sf \to \: 3x + 2 x = 180\: \\ \\ \sf \to \: \: \: \: \: \ : \: \: \: \: \:5x = 180 \\ \\ \: \sf \to \: \: \: \: \: \: \: \: \: \: \:x \: = \frac{180}{5} \\ \\ \sf \to \: \: \: \: \: \: \: \: \: \: \:x \: = \cancel{ \frac{180} {5} } \\ \\ \sf \to \: \: \: \: \: \: \: \: \: \: \purple{x = 36}\\\\\end{gathered}\end {gathered} < /p > < p > < /p > < p > < /p > < p > \end{gathered} →3x+2x=180→ :5x=180→x= 5180 →x= 5180 →x=36

\begin{gathered} < /p > < p > \begin{gathered}\begin{gathered}\sf \to \: 3x \\ \sf \to \: 3 \times 36 \\ \sf \to \red{108 }\\ \\ \\ \sf \to \: 2x \\ \sf \to \: 2 \times 36 \\ \sf \to \orange{72} \\\end{gathered}\end{gathered} \end{gathered}

→3x→3×36→108→2x→2×36→72