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Which of the following species has the shortest bond length ? NO, NO^(+), NO^(2+),NO^(-) |
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Answer» Solution :The electronic configurationsand the bond orders of these species are as follows : (NO has7 + 8 = 15 electrons) `NO: KK sigma_(2s)^(2)sigma_(2s)^(**2)sigma_(2p_(z))^(2)pi_(2p_(x))^(2) pi_(2p_(x))^(**1) ""` Bond order `= (1)/(2) (8-3) = 2.5 ` `NO^(2+)` : One electron is removed from `pi_(2p_(x)) ^(**)` of NO, Bond order =` (1)/(2) (8-4) = 2 ` Thus , ` NO^(+)` has the highest bond order and , therefore, the SHORTEST bond length . |
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