1.

Which of the following species has the shortest bond length ? `NO, NO^(+), NO^(2+),NO^(-)`

Answer» The electronic configurations and the bond orders of these species are as follows : (NO has 7 + 8 = 15
electrons)
`NO: KK sigma_(2s) ^(2)sigma_(2s) ^(**2)sigma_(2p_(z)) ^(2)pi_(2p_(x))^(2) pi_(2p_(x))^(**1) " "` Bond order `= (1)/(2) (8-3) = 2.5 `
`NO^(2+)` : One electron is removed from `pi_(2p_(x)) ^(**)` of NO, Bond order =` (1)/(2) (8-4) = 2 `
Thus , ` NO^(+)` has the highest bond order and , therefore, the shortest bond length .


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