

InterviewSolution
Saved Bookmarks
1. |
Which of the following species has the shortest bond length ? `NO, NO^(+), NO^(2+),NO^(-)` |
Answer» The electronic configurations and the bond orders of these species are as follows : (NO has 7 + 8 = 15 electrons) `NO: KK sigma_(2s) ^(2)sigma_(2s) ^(**2)sigma_(2p_(z)) ^(2)pi_(2p_(x))^(2) pi_(2p_(x))^(**1) " "` Bond order `= (1)/(2) (8-3) = 2.5 ` `NO^(2+)` : One electron is removed from `pi_(2p_(x)) ^(**)` of NO, Bond order =` (1)/(2) (8-4) = 2 ` Thus , ` NO^(+)` has the highest bond order and , therefore, the shortest bond length . |
|