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Answer» The `DeltaG_(y)^(@)`of the sulphide is greater than those for `CS_2` and `H_(2)S`. The `DeltaG_(f)^(@)` is negative for roasting of sulphide ore to oxide. Roastingof thesulphidetotheoxideis thermodynamically feasible. Carbon and HYDROGEN are suitable reducing agents for metal sulphides. Solution :The STANDARD FREE energies of formation `(DeltaG_(f)^(@))` of most of the sulphides are greater than those of `CS_(2)` and `H_(2)S`. Hence, either carbon nor hydrogen can reduce metal sulphides to metal. The standard free energies of formation of oxides are much lower than those of `SO_(2)`. Therefore, oxidation of metal sulphides to metal oxides is thermodynamically favourable. Hence, sulphide ore is roasted to the oxide before REDUCTION.
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