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Which of the following statement is/are correct |
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Answer» The weight of `CaCO_(3)` in the ORIGINAL MIXTURE is `0.5 g`. `((1 "MOL" CO_(2))/(44 g CO_(2)))((1 "mol" CaCO_(3))/("mol"CO_(2)))` `((100 g CaCO_(3))/("mol" CaCO_(3)))` `= (0.22 xx 100)/(44) = 0.5 g CaCO_(3)` b. Moles of `CaCO_(3)=` moles of `Ca` `= ((0.22)/(44)) = 0.005 "mol"` Weight of `Ca = 0.005 xx 40 = 0.2 g Ca` d. % of `Ca = (0.2)/(1.0) xx 100 = 20% Ca` ltbgt Hence, (c ) wrong. |
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