which of the following statement is correct?A. The lesser number of oxidation state in `3d`-series in the beginning of the series is due to the presence of too few electrons to loose or shareB. The lesser number of oxidation states in `3d-series` towards the end of the series is due to the presence of too many electrons and thus fewer empty orbital to share electrons with the ligandsC. (A) and (B) bothD. None is correct

which of the following statement is correct?A. The lesser number of ox

1.	which of the following statement is correct?A. The lesser number of oxidation state in `3d`-series in the beginning of the series is due to the presence of too few electrons to loose or shareB. The lesser number of oxidation states in `3d-series` towards the end of the series is due to the presence of too many electrons and thus fewer empty orbital to share electrons with the ligandsC. (A) and (B) bothD. None is correct
Answer» Correct Answer - C The lesser number of oxidation states in the begining of series can be due to the presence of smaller number of electrons to lose or share `(Sc,Ti)`. On the other hand, at the extreme right hand side end `(Cu,Zn)` lesser number of oxidation state is due to large number of d electrons so that only a fewer orbitals are available in which the electron can share with other for higher valence.

Discussion

No Comment Found

Related InterviewSolutions

(T) imparts violet colour in the flame test `overset("compound"(U)+conc.H_(2)SO_(4))to(V)_("Red gas")overset(NaOH+AgNO_(3))to(W)_("Red ppt.")overset(NH_(3)" soln")to(X)` `(W)_("Red ppt.")overset(dil.HCl)to(Y)_("White ppt.")` `(U)` Sublimes on heating `underset(Delta)overset(NaOH)to(Z)_(gas)` Identify (T) to (Z).A. `T=KMnO_(4),U=HCl,V=Cl_(2),W=HgI_(2),X=Hg(NH_(2))NO_(3),Y=Hg_(2)Cl_(2),Z=N_(2)`B. `T=K_(2)Cr_(2)O_(7),U=NH_(4)Cl,V=CrO_(2)Cl_(2),W=Ag_(2)CrO_(4),X=[Ag(NH_(3))_(2)]^(+),Y=AgCl,Z=NH_(3)`C. `T=K_(2)CrO_(4),U=KCl,V=CrO_(2)Cl_(2),W=HgI_(2),X=Na_(2)CrO_(4),Y=BaCO_(3),Z=NH_(4)Cl`D. `Y=K_(2)MnO_(4),U=NaCl,V=CrO_(3),W=AgNO_(3),X=(NH_(4))_(2)CrO_(4),Y=CaCO_(3),Z=SO_(2)`
Identify (A),(B) and (C). Also explain colour difference between `MCl_(4)` and (B).
When `AgNo_(3)`(aq)` reacts with excess of iodine, we get:A. `AgIO_(3)`B. `HIO_(3)`C. `AgO`D. `HI`
Which of the following halides react(s) with `AgNO_(3(aq))` to give a precipitate that dissolves in `Na_(2)S_(2)O_(3(aq))`A. `HCl`B. `HF`C. `HBr`D. `Hl`
What happen when silver nitrate solution is added to `Na_(2)S_(2)O_(3)` solution and then content is allowed to keep for a longer period?
`Na_(2)S_(2)O_(3)` can be prepared by:A. `Na_(2)SO_(3)` solution + `S("powder")overset("Boiled")to`B. `S+NaOHto`C. `Na_(2)S+Na_(2)CO_(3)+SO_(2)to`D. all of the above.
What takes place when zinc metal is added to an aqueous solution containing magnesium nitrate and silver nitrate? (P). Zn is oxidized (Q). `Mg^(2+)` is reduced. (R). `Ag^(+)` is reduced. (S). No reaction takes place.A. P and Q onlyB. P and R onlyC. P,Q and R onlyD. S only
In the galvanizing process, iron is coated with zinc. The resulting chemical protection is most similar to that provided when:A. a magnesium bar is connected to an iron pipeB. an iron can is plated with tinC. copper pipes are connected using lead solderD. a copper pipe is covered with epoxy paint.
Which metal in the first series of transition metals exhibits+1 oxidation state most frequently and why?A. ScB. TiC. CuD. Ag
How would you account for the following: (i) `Cr^(2+)` is reducing in nature while with the same d-orbital configuration `(d^(4)) Mn^(3+)` is an oxidising agent (ii) In a transition series of metals, the metal which exhibits the greatest number of oxidation state occurs in the middle of the series.

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment