1.

Which of the following statement regarding the pair of complexes is/are incorrect ?

Answer»

Both `K_2[PdCl_4]` and `K_2[PT(o x )_3]` are optically inactive
Both `K_2[PdCl_4]` and `K_2[Pt(o x )_3]` do not form diastereomers
`K_2[Ni(CN)_4] and Co[Hg(SCN)_4]` have same hybridization of CENTRAL atom
`K_2[Ni(CN)_4] and Co[Hg(SCN)_4]` both can show same type of structural ISOMERISM and are diamagnetic

Solution :`[Pt(o x)_3]^(2-)` is optically active due to 3 didentate LIGANDS. `[PdCl_4]^(2-)` and `[Pt( o x)_3]^(2-)` do not show G.I as well ligands are same .
Hybridization of `Ni^(2+)` is `dsp^2` in `[Ni(CN)_4]^(2-)` and that of `Hg^(2+)` is `sp^3` in `[Hg(SCN)_4]^(2-)`
Both `CN^-` and `SCN^-` ligands are ambidentate. Hence both `[Ni(CN)_4]^(2-)` and `[Hg(SCN)_4]^(2-)` show linkage isomerism. `K_2[Ni(CN)_4]` is diamagnetic but `Co[Hg(SCN)_4]` is not as `Co^(2+)` is `d^7` -paramagnetic.


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