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Answer» The `DeltaG_(f)^(@)` of the sulphide is greater than those for `CS_(2)` and `H_(2)S` The `DeltaG_(F)^(@)` is negative for roasting of sulphide ore to oxide. Roasting of the sulphide to the oxide is thermodynamically feasible. Carbon and HYDROGEN are suitable reducing agents for METAL sulphides. Solution :The standard free energies of FORMATION `(DeltaG_(f)^(@))` of most of the sulphides are more negative than those of `CS_(2)` and `H_(2)S`. Hence, neither carbon nor hydrogen can reduce metal sulphides to metal. The standard free energies of formation of OXIDES are much LOWER than those of `SO_(2)` . Therefore , oxidation of metal sulphides to metal oxides is thermodynamically favourable. Hence sulphide ore is roasted to the oxide before reduction.
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