Which of the following statements are correct regardly 17^(th) group e

1.	Which of the following statements are correct regardly 17^(th) group elements
Answer» `I^(-)` reduces `CU^(2+) ` to `Cu^(+)` `Cl^(-)` reduces `Cu^(2+)` to `Cu^(+)` `I_(3)^(-)`exists wheras `Cl_(3)^(-)` does not The bond energy order is `Cl_(2) gt Br_(2) gt F_(2) gt I_(2)` Solution :Due to the low reduction POTENTIAL of `I_(2)`, i.e. `(E_(I_(1)//I^(-))^(@))` , hence `I^(-)` is a good reducing agent and is capable of reducing, `Cu^(2+)` to `Cu^(+)` in `I_(3)^(-)` , there is strong vander Waal's forces of ATTRACTION between `I_(2)` and `I^(-)` due to large size, wheras there is weak vander waal's forces of attraction between `Cl_(2)` and `Cl^(-)` , hence `I_(3)^(-)` exists wheras `Cl_(3)^(-)` does not. In `Cl_(2)`, apart from the Cl-Cl covalent bond, there is `p pi to dpi` coordinate covalent bond between filled p-orbitals of one chlorine atom with empty d-orbitals. ASLO due to small size of F atom, the interatomic repulsion is so high that the F-F bond is weaker than the Br-Br bond. in `I_(2)` due to large size of I atom, the I- bond is very weak . Choice (b) is incorrect because the `E_(Cl_(2)//Cl^(-))^(@)` is so high that it cannot be oxidised to `Cl_(2)` easily which only strong oxidising agents can do, `Cu^(2+)` is not a strong oxidising agent or `E_(Cl_(2)//Cl^(-))^(@) gt E_(Cu^(2+)//Cu^(+))^(@)`.

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