1.

Which of the following wil giveH_(2_((g))) at cathode andO_(2_((g))) at anode on electrolysis using platinum electrodes

Answer»


Solution :For dilute aq. Solution of NACL.
`NaCl=Na^(+)+CL^(-)`
`H_(2)O=H^(+)+OH`
At cathode
`H^(+)` will DISCHARGE SINCE the discharge potential of
`H^(+) lt Na^(+)`
`2H^(+)+2e^(-)toH_(2)(g)`
At anode Due to very lesser amount of `Cl^(-),OH^(-)` ions will discharge at anode
`4OH^(-)toO_(2)+2H_(2)O+4e^(-)`


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