InterviewSolution
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InterviewSolution
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Which of the following will decrease the pH of a 50 ml solution of `0.01 M HCI` ?A. Addition of 50 mL of 0.01 M HClB. Addition of 50 mL of 0.02 M HClC. Addition of 150 mL of 0.02 M HClD. Addition of 5 mL of 1 M HCl |
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Answer» Correct Answer - D For 0.01 M HCl, `|H^(+)| =10^(-2), pH=2` `(A) N_(1)V_(1)+N_(2)V_(2)=N_(3)(V_(1)+V_(2))` `50 xx 0.01+50 xx 0.01 =N_(3)(50+50)` or `N_(3)=(.5 +.5)/(100)=10^(-2),pH=2` (No change) `(B) 50 xx 0.01 +c0 xx 0.002=N_(3)(50+50)` or `N_(3) =(0.5 +0.1 )/(100)=6 xx 10^(-3)` `pH= - log (6 xx 10^(-3))=2.22 (`pH increases) `(C ) 50 xx 0.01 +150 xx 0.002 = N_(3)(50+150)` or `N_(3)=(.5 +.3)/(200)=4 xx 10^(-3)` `pH =-log (4 xx 10^(-3))=2.39 pH (pH ` increases ) `(D) 50 xx 0.01 +5 xx 1 =N_(3)(50+5)` or `N_(3)=(0.5 +5)/(55)=(5.5)/(5)=10^(-1)` `pH =1 (`pH decreases ) |
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