Which of the following will have the minimum no. Of atoms:-(1) 1g Cl2(2) 1g Li(3) 1g Na(4) 1g Au

Which of the following will have the minimum no. Of atoms:-(1) 1g Cl2(

1.	Which of the following will have the minimum no. Of atoms:-(1) 1g Cl2(2) 1g Li(3) 1g Na(4) 1g Au
Answer» 10^10<br>(i) Gram atomic mass of Au= 197 g\xa0Or197g of Au contains = 6.022 x 1023\xa0Therefore 1gm of Au contains = 6.022 x 1023/1971 = 3.06 x 1021\xa0atoms\xa0(ii) Gram atomic mass of Na = 23 gOr23 g of Na contains atoms = 6.022x 1023Or1gm of Na contains atoms = 6.022x1023\xa0/23 1 = 26.2 x1021atoms\xa0(iii) Gram atomic mass of Li = 7Or7g of Li contains atoms = 6.022 x 1023Or1g of Li contains atoms = 6.022 x 1023/7 1= 86.0 x 1021\xa0atoms\xa0(iv) Gram atomic mass of Cl = 71 Or 71g of Cl contains atoms = 6.022x1023Or1 g of Cl contains atoms = 6.022x1023\xa0/71 1= 8.48 x 1021atoms