1.

Which of the following will react with NaOH to form methanol as a major product ?

Answer»

`(CH_3)_4N^(+)I^(-)`
`(CH_3)_3S^(+)I^(-)`
`(CH_3)_3C Cl`
`CH_3-O-CH_3`

Solution :`3^@R-X` will afford alkene as major PRODUCT with NaOH. Due to greater electronegativity of N over S, positive charge on N will MAKE the methyl groups more electron-deficient therefore, `(CH_3)_4N^(+)I^(-)` will UNDERGO nucleophilic substitution more READILY.


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