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Answer» Electrolysis of dilute NaOH solution given `H_(2)` at CATHODE and `O_(2)` at anode. Electrolysis of sulphuric acid (dilute or concentrated) GIVES `H_(2)` at cathode and `O_(2)` at anode. Electrolysis of aqueous KF solution gives fluorine at the anode oxidation of copper anode occurs in the electrolysis of aqueous copper sulphate solution using solution copper electrodes. Solution :(B) is wrong because electrolysis of concentrated `H_(2)SO_(4)` does not GIVE `O_(2)` at the anode. (c) is wrong because electrolysis of aqueous KF solution gives `O_(2)` at the anode and not `F_(2)`.
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