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| 1. |
Which of the function of time represent (a) simple harmonic. (b) periodic but not simple harmonic. and (c) non periodic motion ? Give period for each case of periodic motion (omega is any positive constant), 3cos(pi//4-2omegat) |
| Answer» Solution :`3COS(pi//4-2omegat)= 3cos(2omegat-pi//4)`it is simple HARMONIC with a time PERIOD `T= (2PI)/(2omega)= (pi)/(omega)` | |