1.

Which of the two feasible solutions (12, 10) and (14, 5) of an E.P.P minimises the objective function Z = 5X + 4Y.

Answer»

Here Z (12, 10) = 5(12) + 4(10)= 100 and Z (14, 5) = 5(14) + 4(5) = 90. (14,5) minimises the objective function.



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